(x^3-3x^2-3x-4)/(x+2)

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Solution for (x^3-3x^2-3x-4)/(x+2) equation: 


D( x )

x+2 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-2) U (-2:+oo)

(x^3-(3*x^2)-(3*x)-4)/(x+2) = 0

(x^3-3*x^2-3*x-4)/(x+2) = 0

x^3-3*x^2-3*x-4 = 0

x^3-3*x^2-3*x-4 = 0

{ 1, -1, 2, -2, 4, -4 }

1

x = 1

x^3-3*x^2-3*x-4 = -9

1

-1

x = -1

x^3-3*x^2-3*x-4 = -5

-1

2

x = 2

x^3-3*x^2-3*x-4 = -14

2

-2

x = -2

x^3-3*x^2-3*x-4 = -18

-2

4

x = 4

x^3-3*x^2-3*x-4 = 0

4

x-4

x^2+x+1

x^3-3*x^2-3*x-4

x-4

4*x^2-x^3

x^2-3*x-4

4*x-x^2

x-4

4-x

0

x^2+x+1 = 0

DELTA = 1^2-(1*1*4)

DELTA = -3

DELTA < 0

x in { 4} 

x-4 = 0

(x-4)/(x+2) = 0

x-4 = 0 // + 4

x = 4

x = 4

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